Question

A rock is thrown horizontally from a height of 6.00 m. Which of the following is the time required for the rock to reach the ground ?

Answer 1

Answer:

t=10.95 seg

Explanation:

The vertical component of velocity is 0, so, the time in air can be calculated

$h=v_ot-\frac{1}{2}gt^2\\\\h=0-\frac{1}{2}gt^2~=>t=\sqrt{2gh}=\sqrt{2*10\frac{m}{s^2}*6m}=10.9544~seg$