Question

What is the equation, in slope-intercept form, of the line that has slope 3/4 and passes through the point ( 4,-5 )?

Answer 1

y = (3/4)x - 8

Explanation:

m (gradient/slope) = 3/4

let (x1, y1) be (4, -5)

y - y1 = m(x - x1)
y - (-5) = 3/4 * (x - 4)
y + 5 = (3/4)x - 3
y = (3/4)x - 8