Answer:
Solution given:
the equation of a circle is:
x²+y²-6x-2y+4=0
x²-2*x*3+3²+y²-2y+1²-1²+4=0
(x-3)²+(y-1)²=9+1-4
(x-3)²+(y-1)²=6
comparing above equation with
(a-h)²+(y-k)²=r²
we get
centre (h,k)=(3,1)
radius=√6
option first
(3,1), r = √6 is a required answer.
