Answer:
Sine of C=?
Among the given options which is the correct one.
Step-by-step explanation:
Consider a right-angle triangle ABC.
[tex]angle B=90^{0}[/tex]
In a right angle triangle, one angle [tex]90^{o}[/tex].
The sum of all the angles is [tex]180^{o}[/tex].
[tex]angle A +angle B+angleC=180^{0}angleA+90^{0} +angle C=180^{0}\\angleA+angleC=180^{0} -90^{0} \\angleA+angleC=90^{0} \\angleA=90^{0} -angle C[/tex]
Consider the trigonometric ratios and use the traingle ABC.
[tex]SinC=\frac{AB}{AC}[/tex]
[tex]CosA=\frac{AB}{AC}[/tex]
[tex]angleA=angle(90-C)\\Hence,\\SinC=Cos(90-C)[/tex]
Answer:
OptionF).[tex]Sine of C=Cos(90^{0} -C)[/tex]