Question

Use trigonometric ratios to solve each right triangle. Be sure to rationalize the denominators when you write your answers.

Answer 1

Answer:

$sin(45)=\frac{AC}{AB} =\frac{AC}{12} \\AC=12\times sin(45)=12\times \frac{\sqrt{2}}{2}=6\sqrt{2}\\ cos(45)=\frac{CB}{AB} =\frac{CB}{12} \\CB=12\times cos(45)=12\times \frac{\sqrt{2}}{2}=6\sqrt{2}$

Step-by-step explanation:

$sin(45)=\frac{AC}{AB} =\frac{AC}{12} \\AC=12\times sin(45)=12\times \frac{\sqrt{2}}{2}=6\sqrt{2}\\ cos(45)=\frac{CB}{AB} =\frac{CB}{12} \\CB=12\times cos(45)=12\times \frac{\sqrt{2}}{2}=6\sqrt{2}$