Question

Inside a car that was at STP, a 1.33 L bottle warms up to 130 C. If the volume of the bottle remains constant, what is the pressure, in atm, inside the hot water bottle?

Answer 1

Answer:

$P_2=1.48atm$

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to infer this problem is about the application of the Gay-Lussac's gas law to relate the initial and final pressure and temperature as shown below:

$\frac{P_2}{T_2} =\frac{P_1}{T_1\\ }$

Thus, solving for the final pressure, P2, and using the temperatures in Kelvins, we obtain:

$P_2 =\frac{P_1T_2}{T_1 }\\\\P_2 =\frac{1atm*403.15K}{273.15K}\\\\P_2=1.48atm$

Regards!