Answer:
They have enough.
[tex]2\frac{6}{12} <2\frac{7}{12}[/tex]
Step-by-step explanation:
[tex]\frac{4}{3}+ \frac{5}{4}[/tex]
4 = 2 × 2
3 = 3 × 1
LCM of 4 and 3
= 2 × 2 × 3 × 1
= 12
[tex]4(\frac{4}{3})+ 3(\frac{5}{4})[/tex]
[tex]\frac{16}{12}+ \frac{15}{12}[/tex]
[tex]\frac{31}{12} =2\frac{7}{12}[/tex]
[tex]2\frac{1}{2} =2\frac{6}{12}[/tex]
[tex]2\frac{6}{12} <2\frac{7}{12}[/tex]