Answer:
"12 trips" is the correct answer.
Explanation:
Given:
Density,
= 880 kg/m
Volume,
= 70.3 m³
Safe load,
= 5300 kg
Now,
The total mass of dump will be:
= [tex]Density\times Volume[/tex]
= [tex]880\times 70.3[/tex]
= [tex]61864 \ Kg[/tex]
By going through the safe mode, the number of trips will be:
= [tex]\frac{Total \ mass}{Safe \ load}[/tex]
= [tex]\frac{61864}{5300}[/tex]
= [tex]11.57 \[/tex]
hence,
By going through the volume, the number of trips will be:
= [tex]\frac{70.3}{9}[/tex]
= [tex]7.8[/tex]
Thus the truck needs to make 11.57 trips i.e., 12 trips.