Mariano is standing at the top of a hill when he kicks a soccer ball up into the air. The height of the hill is h feet, and the ball is kicked with an initial velocity of v feet per second. The height of the ball above the bottom of the hill after t seconds is given by the polynomial –16t2 + vt + h. Find the height of the ball after 2 seconds if it was kicked from the top of a 60 foot tall hill at 84 feet per second.

A height function exists as a function that quantifies the intricacy of mathematical objects. The height of an object, h(t), exists defined by the formula [tex]-16 t^{2}[/tex] + vt + h.

Given: Let, the polynomial equation be [tex]-16 t^{2}[/tex] + vt + h

h = 20 ft and v = 72 ft/s

y = [tex]-16 t^{2}[/tex] + 72t + 20

To estimate the height of the ball after 2 seconds

substitute the value of t = 2, then

y = -16 [tex]\times[/tex] 4 + 72 [tex]\times[/tex] 2 + 20

= -64 + 144 + 20

= 100 feet

The height of the ball after 2 seconds is 100 feet.

To learn more about the height of the object

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