Question

5) A moving 2 kg object has an initial velocity of 10 m/s. It comes to a stop on a rough
surface after travelling a distance of 5m. Calculate:
a) the kinetic energy of the subject

b) the frictional force acting on the object

c) the heat energy produced​

Answer 1

Answer:

a) kinetic energy=0.5×mass×speed²

kinetic energy=0.5×2×10²=100 joules

Explanation:

im not sure about the rest :(

Answer 2

Answer:

a) 100J

b)20N

c) 100J

Explanation:

A) KE = 0.5 x mass x velocity^2

= 0.5 x 2 x 10^2

= 100 J

B) Work done = Force x distance

Since work done = energy transferred

Energy transferred = Force x Distance

Energy transferred/ Distance = Force

100/5 = 20 N

C) Let's assume that all the Kinetic energy of the subject get's transferred into heat energy

Therefore Kinetic energy = Heat energy = 100 J