Question

Find the zeros of the quadratic function: y= 6(7x + 9)(8x - 3).
A) (-9/7,0), (3/8,0)
B)(-7/9,0), (8/3,0)
C) (-3/8,0), (°/7,0)
D) (-8/3,0), (7/9,0)

Answer 1

Answer:

A) (-9/7,0), (3/8,0)

Step-by-step explanation:

Zeros of a quadratic function:

x for which y = 0.

In this question:

$y = 6(7x + 9)(8x - 3)$

It's 0 if one of the factors is 0. 6 is never 0, now about the other to:

$7x + 9 = 0$

$7x = -9$

$x = -\frac{9}{7}$

So (-9/7, 0) is a zero of the quadratic function.

The other is:

$8x - 3 = 0$

$8x = 3$

$x = \frac{3}{8}$

(3/8,0) is the other zero.

Thus, the correct answer is given by option A.