Question

3. If a gas exerts 1.2 atm of pressure at a volume of 31 liters and a temperature of 360K, how many moles of the gas are in the container.​

Answer 1

The answer is 1.26 Mol

n = PV/RT= (1.2 atm)(31 L) / (0.0821 )(360K) = 1.26 mol H2