Question

A gumball machine has 21 red gumballs, 24 yellow gumballs, and 15 blue gumballs. The gumballs are randomly mixed. What is the probability that the gumball machine dispenses 2 red gumballs in a row?

Answer 1

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total gumballs = 21 + 24 + 15

total gumballs = 60

no. of red gumballs = 21

twice into no. of red balls and total gumballs = 41/120

answer = 41/120

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Answer 2

The probability would be 7/59
This is because there are 69 total gum balls , and 21 are red.
You have a 21/60 chance of getting red the first time, and a 20/59 chance of getting another red the second time you deepened a gum all.
Now you multiply those to probabilities (21/60 x 20/59) and you get 420/3540 which simplifies to 7/59

I hope this helps!