Question

WILL GIVE BRAINIEST PLS HELP RN :
In the backyard calorimetry lab I had 189.5 grams of water in my Batman thermos. The water started out at a
temperature of 16.4 °C. After a few minutes the water cooled to 8.9°C. How much thermal energy did the
water use to melt the ice cube?

Answer 1

Answer:

Q = 5949.35 J

Explanation:

Given that,

The mass of water, m = 189.5 grams

Initial temperature, T = 16.4 °C

Final temperature, T' = 8.9°C

We need to find the thermal energy the water use to melt the ice cube. The thermal energy is given by :

$Q=mc\Delta T$

Where

c is the specific heat of the water, c = 4.186 joule/gram °C

So,

$Q=189.5\times 4.186 \times (8.9-16.4)\\Q=-5949.35\ J$

So, the required amount heat is equal to 5949.35 J.