Answer:
F2: 1/4 phenotype Ad (genotype Ad/Ad), 1/2 phenotype AD (genotype Ad/aD): 1/4 phenotype aD (genotype aD/aD)
Explanation:
In this case, A and D loci are strongly linked and there is little or no recombination between them. Therefore, Ad/Ad and aD/aD individuals will produce only one type of gametes (i.e., individuals Ad/Ad only can produce Ad gametes, while aD/aD individuals only can produce aD gametes), thereby all F1 will be Ad/ aD. Finally, Ad/aD individuals can produce two types of gametes: Ad and aD, thereby the F2 will be 1/4 Ad/Ad (phenotype Ad), 1/2 Ad/aD (phenotype AD) and 1/4 aD/aD (phenotype aD)
Parental cross: Ad/Ad x aD/aD
F1 generation: Ad/aD
F2 generation:
Ad aD
Ad Ad/Ad Ad/aD
aD Ad/aD aD/aD
F2 generation: 1/4 Ad/Ad (phenotype Ad), 1/2 Ad/aD (phenotype AD) and 1/4 aD/aD (phenotype aD)