Question

A 9.2 resistor and a 5.2 resistor are connected in series with a battery. The potential difference across the 5.2 resistor is measured as 12 V. Find the potential difference across the battery.

Answer 1

Answer:

V = 33.12 V

Explanation:

Given that,

A 9.2 resistor and a 5.2 resistor are connected in series with a battery.

The potential difference across the 5.2 resistors is measured as 12 V.

In series combination of resistors, the current is same throughout the circuit. Let I is the current. Using Ohm's law,

$I=\dfrac{V}{R}$

Put all the values,

$I=\dfrac{12}{5.2}\\\\I=2.30\ A$

The equivalent resistance is :

R = 9.2 + 5.2

= 14.4 ohms

Let V os the potential difference across the battery. So,

$V=2.3\times 14.4\\\\V=33.12\ V$

So, the potential difference across the battery is equal to 33.12 V.