Answer: [tex]103,108[/tex]
Step-by-step explanation:
Given
There are total of 211 coins
The worth of the coins is [tex]\$37.30[/tex]
Suppose there are x dimes and y quarters
A dime is equivalent to 10 cents and quarter is equivalent to 25 cents
[tex]\therefore x+y=211\quad \ldots(i)\\\Rightarrow 0.1x+0.25y=37.30\\\Rightarrow x+2.5y=373\quad \ldots(ii)[/tex]
Solving (i) and (ii) we get
[tex]x=103,y=108[/tex]
Therefore, student collects 103 dimes and 108 quarters.