Answer:
If the perimeter of a square is 28 inches and the area of the square is (x2 + 4x + 4) square inches, and x is a both a real and a positive number, then the value of x must be 5.
Step-by-step explanation:
All sides of a square are equal length.
The area of a square is the side length squared.
perimeter p, side length s, area a, and variable x.
p = 28. s = ? a = x^2 + 4x + 4. x = ?
p = 28
p = 4s.
28 = 4s.
7 = s.
a = s^2.
s = 7.
a = 7^2.
a = 49.
a = x^2 + 4x + 4.
a = 49.
x^2 + 4x + 4 = 49.
factor x^2 + 4x + 4.
(x+2)(x+2) = 49.
(x+2)^2 = 49.
√ ((x+2)^2) = √49.
take positive answer.
x+2 = 7
x = 5.
