Question

Coherent monochromatic light falls perpendicularly on two slits (each of width 0.10 mm) separated by 0.50 mm. In the resulting interference pattern on a screen 2.80 m away, adjacent bright fringes are separated by 2.80 mm. (a)What is the wavelength of the light that falls on the slits

Answer 1

Answer:

The correct answer is "$0.5\times 10^{-6} \ m$".

Explanation:

Given:

$\frac{\lambda D}{d} =2.8\times 10^{-3}$

$d = 0.5\times 10^{-3}$

$D = 2.80$

Now,

The wavelength will be:

⇒ $\lambda = 2.8\times 10^{-3}\times \frac{d}{D}$

By putting the values, we get

⇒    $=\frac{2.8\times 10^{-3}\times 0.5\times 10^{-3}}{2.8}$

⇒    $=\frac{1.4\times 10^{-6}}{2.8}$

⇒    $=0.5\times 10^{-6} \ m$