Question

A closely wound, circular coil with radius 2.80 cm has 790 turns. Part A What must the current in the coil be if the magnetic field at the center of the coil is 0.0760 T

Answer 1

Answer:

$I=11.1A$

Explanation:

From the question we are told that:

Radius $R=2.80$

Turns $N=790$

Magnetic field B=0.0760

Generally the equation for Magnetic field at the center of the coil is mathematically given by

 $B=\frac{\mu NI}{2r}$

 $0.076=\frac{4\p*10^-^7*790*I}{2*0.028}$

 $I=\frac{0.076*2*0.028}{4\p*10^{-7}*790}$

 $I=11.1A$