Question

Every morning Ramona misses her bus with probability 1/10, independently of other mornings. What is the probability that next week she catches her bus on Monday, Tuesday, and Thursday, but misses her bus on Wednesday and Friday

Answer 1

Answer:

The probability is $\frac{729}{100000}$.

Step-by-step explanation:

probability of missing the bus = 1/10

Probability of catching the bus = 1 - 1/10 = 9 /10

So, the required probability is

$\frac{9}{10}\times \frac {9}{10}\times \frac {1}{10}\times \frac {9}{10}\times \frac {1}{10}$

$\frac{729}{100000}$