Question

(7x+1)(2x−3)=0 solve for roots​

Answer 1

Answer:

x = - $\frac{1}{7}$, x = $\frac{3}{2}$

Step-by-step explanation:

Given

(7x + 1)(2x - 3) = 0 ← in standard zero product form

Equate each factor to zero and solve for x

7x + 1 = 0 ⇒ 7x = - 1 ⇒ x = - $\frac{1}{7}$

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = $\frac{3}{2}$

Answer 2

Answer:

x = - 1 / 7   and x = 3 / 2

Step-by-step explanation:

14x2 - 21 x + 2x- 3 = 0

14x2  - 19x -3 = 0

x = 1 9 + 23 / 28 = 3 / 2

x = 19 - 23 / 28 = - 1 / 7

7x + 1 = 0 ⇒ 7x = - 1 = -1 / 7

2x - 3 = 0 ⇒ 2x = 3 = 2/ 3

Hope this answer helps you :)

Have a great day

Mark brainliest