Question

What is the probability of rolling a six-sided number cube and getting an odd number or a number less than 4?

Answer 1

Answer:

$Pr(Odd\ or\ <4) = \frac{2}{3}$

Step-by-step explanation:

Given

$S = \{1,2,3,4,5,6\}$ --- roll of a die

$n(S) = 6$ ---- the sample size

$Odd = \{1,3,5\}$

$<4 = \{1,2,3\}$

Required

$Pr(Odd\ or\ <4)$

First, list out the event of odd or <4

$Odd\ or\ <4 = \{1,2,3,5\}$

So, the probability is:

$Pr(Odd\ or\ <4) = \frac{n(Odd\ or\ <4)}{n(S)}$

$Pr(Odd\ or\ <4) = \frac{4}{6}$

Simplify

$Pr(Odd\ or\ <4) = \frac{2}{3}$