Answer:
0.034 L
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 0.055 L
Initial pressure (P₁) = stp = 1 atm
Initial temperature (T₁) = stp = 273 K
Final pressure (P₂) = 2.8 atm
Final temperature (T₂) = 195 °C = 195 °C + 273 = 468 K
Final volume (V₂) =?
The final volume of the gas can be obtained as follow:
P₁V₁ / T₁ = P₂V₂ / T₂
1 × 0.055 / 273 = 2.8 × V₂ / 468
0.055 / 273 = 2.8 × V₂ / 468
Cross multiply
273 × 2.8 × V₂ = 0.055 × 468
764.4 × V₂ = 25.74
Divide both side by 764.4
V₂ = 25.74 / 764.4
V₂ = 0.034 L
Therefore, the new volume of the gas is 0.034 L.
