Question

How many liters of 10% silver iodide mixed with 9 liter of a 4%silver iodide solution to get 6% solution

Answer 1

Answer:

The correct answer is "4.5 liters". A further explanation is provided below.

Step-by-step explanation:

Let the solution needed be "x".

then, according to the question,

⇒ $4 \ percent(9)+10 \ percent(x)=6 \ percent(9+x)$

By solving the above expression, we get

⇒ $0.04\times 9+0.1x=0.06\times 9+0,06\times x$

⇒                $0.04 x=0.54-0.36$

⇒                $0.04x=0.18$

⇒                      $x=\frac{0.18}{0.04}$

⇒                         $=4.5 \ liters$