Question

PLEASE HELP
what is the perimeter of a quadrilateral with vertices at (1,5), (6,5), (1,11), and (6,11)? enter the answer in the Ⴆσx

Answer 1

Answer:

perimeter = 25.62 units

Step-by-step explanation:

Let the quadrilateral be ABCD

A = (1, 5), B = (6, 5), C= (1, 11) , D = (6, 11)

To find the perimeter we need to add the lengths of sides AB , BC, CD, and AD.

Lets find the length of all sides using distance formula;

$distance = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

$AB = \sqrt{(1-6)^2+(5-5)^2} = \sqrt{25} = 5units\\\\BC= \sqrt{(6-1)^2+(5-11)^2} = \sqrt{25+36} =\sqrt{61} units\\\\CD=\sqrt{(1-6)^2 + (11-11)^2} = \sqrt{25} = 5units\\\\AD = \sqrt{(1-6)^2+(5-11)^2} = \sqrt{25+36} = \sqrt{61}units$

Perimeter = AB + BC + CD + AD

               $=10 + 2\sqrt{61} units$ = 25.62 units