Question

-ww.A
m = 15.0 kg
The block at Position A is released from the spring with 100 J of elastic potential energy. How
much kinetic energy does the block have at Position B? Explain how you know.

Answer 1

Answer:

v = 3.65 m / s

Explanation:

In this exercise we use the conservation of mechanical energy

starting point. Point A compressed spring

          Em₀ = 100 J

final point. Point B uncompressed spring

         Em_f = K = ½ m v²

energy is conserved

         Em₀ = Em₀_f

         100 = ½ m v²

         v = $\sqrt{ \frac{2 \ 100 }{m} }$

         v = $\sqrt {200/15}$

         

         v = 3.65 m / s