Answer: Moles are found in a 350.mL solution of 13.5M [tex]HNO_{3}[/tex] are 4.725 mol.
Explanation:
Given: Volume = 350 mL (1 mL = 0.001 L) = 0.350 L
Molarity = 13.5 M
Molarity is the number of moles of a substance present in a liter of solution.
Therefore, moles of [tex]HNO_{3}[/tex] present in the given solution are calculated as follows.
[tex]Molarity = \frac{moles}{Volume (in L)}\\13.5 M = \frac{moles}{0.350 L}\\moles = 4.725 mol[/tex]
Thus, we can conclude that moles found in a 350.mL solution of 13.5M [tex]HNO_{3}[/tex] are 4.725 mol.
