Question

If a spinner for a game is spun once, there is a 25% chance it will land on
orange. What is the chance that the spinner will not land on orange on both
the first and second spin in a game? Calculate the probability as a decimal
rounded to the nearest TENTH.

Answer 1

Answer:

$Pr = 0.6$

Step-by-step explanation:

Given

Let

$O \to Orange$

So:

$P(O) = 25\%$ --- probability of O

$n=2$ --- Number of spin

Using the complement rule, the probability that a spin will not land on orange is:

$P(O') = 1 - P(O)$

$P(O') = 1 - 25\%$

Express as decimal

$P(O') = 1 - 0.25$

$P(O') = 0.75$

On two spins, the probability that it will not land on orange is:

$Pr = P(O') * P(O')$

So, we have:

$Pr = 0.75* 0.75$

$Pr = 0.5625$

$Pr = 0.6$ --- approximated