Question

11
1. If 325 grams of sodium nitrate are added to water to make the total solution volume 5.5 L,
what is the concentration (molarity) of this solution?

Answer 1

Answer:  0.695 mol/L

Explanation:

To find the final concentration of the solution, we must first identify the moles of the solute (NaNO₃):

   moles = mass ÷ molar mass

∴ moles of NaNO₃ = 325 g ÷ 84.995 g/mol

                              =  3.824 mol

Now, since the final volume is 5.5 L and this volume contains the 3.824 moles of NaNO₃,

then the molarity of the solution = 3.824 mol ÷ 5.5 L

                                                     =  0.695 mol/L