What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point (-3, 1)?

Answer:
[tex]y-1=\frac{3}{2} (x+3)[/tex]
Step-by-step explanation:
Slope of the line drawn is -6 ÷ -4 = [tex]\frac{3}{2}[/tex]
Point slope is y - y1 = m(x - x1)
y1 = 1, x1 = -3
[tex]y-1=\frac{3}{2} (x+3)[/tex]