Answer:
The theoretical yield of sulfur trioxide is 88.0 Litres
Explanation:
The chemical reaction occurring between oxygen and sulfur dioxide is given in the chemical equation below :
2SO₂ + O₂ ----> 2SO₃
From the equation of reaction, 2 moles of sulfur dioxide reacts with 1 mole of oxygen to produce 2 moles of sulfur trioxide.
Volume of 1 mole of a gas at STP is 22.4 L
Number of moles of gas in 44.0 L = 44.0/22.4 moles
1 mole of oxygen reacts with 2 moles sulfur dioxide to produce 2 moles of sulfur trioxide;
44/22.4 moles of oxygen will react with excess sulfur dioxide to produce 2 × 44/22.4 moles of sulfur trioxide = 88/22.4 moles of sulfur trioxide
88/22.4 moles of sulfur trioxide will have a volume of 88/22.4 × 22.4 Litres = 88.0 Litres
Therefore, the theoretical yield of sulfur trioxide is 88.0 Litres
