Question

19- What is the equation of the line that is perpendicular to the given line and has an x-intercept of 6? O y= 4 -10 86 8 10 x --**+ 8 O y=-3x+6 O y= 4X-8 O ya x-6 |(4,2) 5) 10.​

Answer 1

Answer:

$y=\frac{4}{3}x -8$

Step-by-step explanation:

So first find the slope of the given line

-2 - 4 = -6

4 + 4 = 8

-6 ÷ 8 = $-\frac{3}{4}$

The slope of a line perpendicular to another line is the opposite reciprocal of the given slope.

The opposite reciprocal of $-\frac{3}{4}$ is $\frac{4}{3}$

So now all we need to finish the slope intercept form y = mx + b is b, which is the y intercept.

$y=\frac{4}{3}x+b$

Now that they give us the X intercept, you can plug in the values (6, 0).

$0=8+b$

b = -8