Question

Three resistors of values 2 Q, 3 Q and 5 Q are connected in series with a battery of voltage 6.0 V. Calculate the current through each of the resistors, and the current through the battery.

Answer 1

Answer:

Current = 0.6 A

Explanation:

Given that,

Three resistors 2 ohms, 3 ohms and 5 ohms are connected in series with a battery of voltage 6 V.

In series combination of resistors, the current through each resistor is the same while the voltage divides.

The equivalent resistance in this case is given by :

$R_{eq}=R_1+R_2+....$

Put all the values,

$R_{eq}=2+3+5\\\\R_{eq}=10\ \Omega$

Let I be the current. Using Ohm's law,

$V=IR\\\\I=\dfrac{V}{R}\\\\I=\dfrac{6}{10}\\\\I=0.6\ A$

So, the current through each resistor and the current through the battery is equal to 0.6 A.