Answer:
(-1,6) ; (-2,11)
Step-by-step explanation:
y= x^2-2x +3
y= -5x + 1
the best way to proceed is substitute the value of y shows in the second equation in the first equation (general rule: substitute the value shows in the linear equation in the quadratic equation)
-5x + 1 = x^2-2x+3
x^2 +3x + 2 = 0
(x+2)(x+1) = 0
x = -2
x = -1
Solution 1
x = -1
y = 5 + 1 = 6
Solution 2
x = -2
y = 10 + 1 = 11
