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Answer:
h(g(x)) = (1/5)x² +4/5
Step-by-step explanation:
[tex](h\circ g)(x)=h(g(x))=h(x^2+2) = \dfrac{(x^2+2)+2}{5}=\dfrac{x^2+4}{5}\\\\\boxed{(h\circ g)(x)=\dfrac{1}{5}x^2+\dfrac{4}{5}}[/tex]
