Find the value of csc 0, if cos 0= - 2/3 ; 180 < 0< 270

Answer:
D
Step-by-step explanation:
apply pythagorean theorem to find sin of theta.
[tex] \cos( \frac{2}{3} ) {}^{2} + \sin(x) {}^{2} = 1[/tex]
[tex] (\frac{4}{9}) {}^{2} + \sin(x) {}^{2} = 1[/tex]
[tex] \sin(x) {}^{2} = \frac{5}{9} [/tex]
[tex] \sin(x) = \frac{ \sqrt{5} }{3} [/tex]
Find the reciprocal to find find csc.
[tex] \frac{3}{ \sqrt{5} } [/tex]
rationalize the denominator.
[tex] \frac{3}{ \sqrt{5} } \times \frac{ \sqrt{5} }{ \sqrt{5} } = \frac{3 \sqrt{5} }{5} [/tex]
Csc is negative in the 3rd quadrant.
so the answer is
[tex] - \frac{3 \sqrt{5} }{5} [/tex]
D is the answer.