Question

a rectangular piece of land is 73/3 meter long and 61/4 meter wide.Find it's perimeter. Please solve it
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Answer 1

Answer:

49 1/6 meters

Step-by-step explanation:

P = 2(73/3) + 2(61/4)

= 146/3 + 61/2

= 48 2/3 + 30 1/2

= 48 4/6 + 30 3/6

= 48 + 7/6

= 48 + 1 1/6

= 49 1/6

Answer 2

Answer:

$Perimeter = 2 (length + width)$

               $= 2(\frac{73}{3} + \frac{61}{4})\\\\=2(\frac{292 + 183}{12})\\\\= \frac{475}{6}m$