the function h=-16t^2+48t represents the height h (in feet) of a kickball t seconds after it is kicked from the ground

Respuesta :

Answer:

36 feet

Step-by-step explanation:

Given

[tex]h(t) = -16t^2 + 48t[/tex]

Required

Determine the maximum height attained

First, calculate the time to reach maximum height;

In a quadratic equation;

[tex]y = ax^2 + bx + c[/tex]

The maximum is:

[tex]x = -\frac{b}{2a}[/tex]

So, we have:

[tex]t = -\frac{b}{2a}[/tex]

Where

[tex]a = -16; b = 48[/tex]

So:

[tex]t = -\frac{b}{2a}[/tex]

[tex]t = -\frac{48}{2 * -16}[/tex]

[tex]t = -\frac{48}{-32}[/tex]

[tex]t = \frac{48}{32}[/tex]

[tex]t = 1.5[/tex]

The maximum height is at: [tex]t = 1.5[/tex]

So, we have:

[tex]h(t) = -16t^2 + 48t[/tex]

[tex]h_{max}=-16 * 1.5^2 + 48 * 1.5[/tex]

[tex]h_{max}=36[/tex]

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