Answer:
Potential difference, V = -0.000224 Volts
Explanation:
Given the following data;
Quantity of charge = 6.93*10-4 C
Energy = -3.09 J
To find the electric potential V at that point?
Mathematically, the energy transferred per unit of charge is given by the formula;
E = QV
Where:
E is the energy
Q is the quantity of charge
V is the potential difference.
Substituting into the formula, we have;
[tex] -3.09 = 6.93*10^{-4} * V [/tex]
[tex] V = \frac {6.93*10^{-4}}{-3.09} [/tex]
Potential difference, V = -0.000224 Volts
