Question

Lil' HydroPhil owns five pieces of precious apparel and wants to choose two to wear to the awards show. He defines his precious apparel as: platinum nose ring, diamond shirt, titanium boots, suede pants, and beryllium hat. Assuming the selection is random and each has an equally likely outcome, determine the probability HydroPhil chooses a combination that includes the suede pants.

Answer 1

Answer:

The probability HydroPhil chooses a combination that includes the suede pants is 0.40

Step-by-step explanation:

Given

Let

$P \to Platin um\ no se\ ri ng$

$D \to Diamond\ shirt$

$T \to Titanium\ boots$

$S\to Suede\ pants$

$B\to Beryllium\ hat$

Required

Probability of selecting a combination that has S

First, list out all possible combinations (A) of 2

$A = \{PD, PT, PS, PB, DT, DS, DB, TS, TB, SB\}$

The sample size is:

$n(A) = 10$

The combinations that has S are:

$S \to \{PS, DS, TS, SB\}$

The size is:

$n(S) = 4$

So, the probability that he choose the combination that has S is:

$Pr = \frac{n(S)}{n(A)}$

$Pr = \frac{4}{10}$

$Pr = 0.40$