Question

In circle N with m \angle MNP= 48m∠MNP=48 and MN=16MN=16 units find area of sector MNP. Round to the nearest hundredth.

Answer 1

Answer:

$A=107 square\ unit$

Step-by-step explanation:

From the question we are told that:

 $\angle MNP= 48m$

 $\angle MN=16 unit$

Generally the equation for Area of a sector A is mathematically given by

 $A=\frac{\theta}{360}*\pi*r^2$

 $A=\frac{48}{360}*3.14*16^2$

 $A=107.18 square\ unit$

 $A=107 square\ unit$

Answer 2

Answer:

10.4

Step-by-step explanation:

Area of sector=central angle/360(area)

=46/360(π5^2)

=10.04