Answer:
8.136×10⁻⁵ J
Explanation:
Applying,
Q = Cv................ Equation 1
Where Q = Charge on the capacitor, v = voltage of the battery, C = capacitance of the capacitor.
From the question,
Given: C = 6.78μF = 6.78×10⁻⁶ F, v = 12 V
Substitute these values into equation 1
Q = (6.78×10⁻⁶ )(12)
Q = 8.136×10⁻⁵ J
Hence the charge on the capacitor is 8.136×10⁻⁵ J
