Answer:
[tex]V_1=82.6mL[/tex]
Explanation:
Hello there!
In this case, according to this question, we will need to deal with this dilution problem, because it is asking for the volume of a 12.1-M stock solution of HCl. In such a way, we can use the following equation, under the assumption of no change in the number of moles in the solution:
[tex]M_2V_2=M_1V_1[/tex]
Thus, we solve for the initial volume, V1, as shown below:
[tex]V_1=\frac{M_2V_2}{M_1}[/tex]
And plug in the initial concentration and final concentration and volume to obtain:
[tex]V_1=\frac{2000mL*0.500M}{12.1M}\\\\V_1=82.6mL[/tex]
Regards!