Answer:
[tex](a)\ -16t^2 + 7t + 63=0[/tex]
[tex](b)\ t = 2.215[/tex]
Step-by-step explanation:
Given
[tex]h(t) = -16t^2 + 7t + 63[/tex]
Solving (a): Equation when it hits the ground.
This means that [tex]h(t) = 0[/tex]
So, we have:
[tex]h(t) = -16t^2 + 7t + 63[/tex]
[tex]-16t^2 + 7t + 63=0[/tex]
Solving (b): The value of t in (a)
[tex]-16t^2 + 7t + 63=0[/tex]
Using quadratic formula, we have:
[tex]t = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}[/tex]
This gives:
[tex]t = \frac{-7 \± \sqrt{7^2 - 4*-16*63}}{2*-16}[/tex]
[tex]t = \frac{-7 \± \sqrt{49+ 4032}}{2*-16}[/tex]
[tex]t = \frac{-7 \± \sqrt{4081}}{-32}[/tex]
[tex]t = \frac{-7 \± 63.88}{-32}[/tex]
Split
[tex]t = \frac{-7 + 63.88}{-32}; or\ t = \frac{-7 - 63.88}{-32}[/tex]
[tex]t = \frac{56.88}{-32}; or\ t = \frac{-70.88}{-32}[/tex]
[tex]t = -1.7775; or\ t = 2.215[/tex]
Time can't be negative; So:
[tex]t = 2.215[/tex]