To Prove :
a×(b+c) = a×b + a×c
Solution :
Solving L.H.S. we get :
[tex]a(b+c ) = \dfrac{1}{3}( \dfrac{1}{5}-\dfrac{2}{3})\\\\= -\dfrac{7}{45}[/tex]
Solving R.H.S. we get :
[tex]a\times b + a\times c = \dfrac{1}{3}\times \dfrac{1}{5} + \dfrac{1}{3}\times (-\dfrac{2}{3})\\\\= -\dfrac{7}{45}[/tex]
Since, L.H.S = R.H.S
Therefore, the given equation is correct.