Answer:
32 cm³
Explanation:
The given gas data are;
The relative density of oxygen = 16
The relative density of carbon dioxide = 12
The time it takes 25 cm³ of carbon dioxide to effuse out = 75 seconds'
The duration of effusion of the oxygen = 96 seconds
The rate of effusion of carbon dioxide, R1 = 25 cm³/(75 sec) = (1/3) cm³/sec
According to Graham's law of diffusion and effusion of a gas, we have;
[tex]\dfrac{Rate \ of \ effudion \ of \ gas \ 1}{Rate \ of \ effudion \ of \ gas \ 2} =\dfrac{The \ relative \ density \ of \ gas \ 2}{The \ relative \ density \ of \ gas \ 1}[/tex]
Therefore, we have;
[tex]\dfrac{Rate \ of \ effudion \ of \ oxygen}{(1/3)} =\dfrac{12}{16}[/tex]
[tex]The \ rate \ of \ effudion \ of \ oxygen}=\dfrac{12}{16} \times \left(\dfrac{1}{3 } \ cm^3/sec\right ) = \dfrac{1}{4} \ cm^3/sec[/tex]
The volume of effusion = The rate of effusion × Time
The volume of the oxygen that will effuse in 96 seconds is given as follows;
The rate of effusion of a gas × Time
V = The rate of effusion of oxygen × Time = (1/3) cm³/sec × 96 sec = 32 cm³
The volume of oxygen that will effuse in 96 seconds, V = 32 cm³.
