Respuesta :
Answer: A=750 +75*t
B=900 +25*t
There would be 975 students in each high school in year 3 when they are expected to have the same number of students.
Step-by-step explanation:
A = B
750 +75*t=900 + 25*t
Solving:
75*t -25*t= 900 - 750
50*t= 150
t=3
This indicates that in year 3 both High Schools are projected to have the same number of students. To get that amount, you simply replace this value in the expressions:
A=750 +75*t= 750 +75*3= 975
B=900 + 25*t=900 + 25*3= 975
There would be 975 students in each high school in year 3 when they are expected to have the same number of students.
Equation for high school A: A(t)=750+45t
Equation for high school B: B(t)=850+25t
750+45t=850+25t, solve for t:
45t-25t=850-750
20t=100
t=5
Answer: After 5 years, both high schools will have the same number of students.
Check:
750+45t=750+(45*5)=750+225=975
850+25t=850+(25*5)=850+125=975
Equation for high school B: B(t)=850+25t
750+45t=850+25t, solve for t:
45t-25t=850-750
20t=100
t=5
Answer: After 5 years, both high schools will have the same number of students.
Check:
750+45t=750+(45*5)=750+225=975
850+25t=850+(25*5)=850+125=975