Answer:
[tex]CH_3COOH+CH_3CH_2CH_2CH_2OH\rightarrow CH_3COOCH_2CH_2CH_2CH_3+H_2O[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to realize this is a question about esterification, process whereby a carboxylic acid and an alcohol react to produce water an an ester, we can set it up as shown below:
[tex]CH_3COOH+CH_3CH_2CH_2CH_2OH[/tex]
For the reaction between ethanoic acid and butanol; and therefore, the products side is:
[tex]CH_3COOCH_2CH_2CH_2CH_3+H_2O[/tex]
It means that the overall equation is:
[tex]CH_3COOH+CH_3CH_2CH_2CH_2OH\rightarrow CH_3COOCH_2CH_2CH_2CH_3+H_2O[/tex]
And the ester product is butyl ethanoate.
Regards!