Question

What is the equation of the line that is parallel to y=1/3x+4 and passes through (-3, 1);

A y=-3x – 8
B y= 3x + 10
C y=-1/3x
D y= 1/3x+2

Answer 1

Answer:

Step-by-step explanation:

$y = \frac{1}{3} x +4$ , $slope, m_1 = \frac{1}{3}$

Let the slope of the new line be $m_2$

Since the lines are parallel , $m_1 = m_2$

                                               $m_2 = \frac{1}{3}$

$(x_1, y_1) = (-3, 1) \ , \ m_2 = \frac{1}{3}\\\\Equation \ of \ the \ new \ line : (y - y_1) = m(x - x_1)$

                                        $y - 1 = \frac{1}{3}(x -(-3)) \\\\y - 1 = \frac{1}{3}(x +3)\\\\y - 1 =\frac{1} {3}x + 1 \\\\y = \frac{1}{3}x + 2$